Kirchhoff's voltage law (KVL)
Kirchhoff's voltage law (KVL) The sum of
all the voltages around a loop is equal to zero. This law is
also called Kirchhoff's second law, Kirchhoff's loop
(or mesh) rule, and Kirchhoff's second rule.
- Make a circuit using the same Resistors (R1 = R2 = R3 = 1k Ω) and voltage source i.e. Vs =15v.
Figure 1
- Then simulate the circuit and we got the voltage at each node and then find the voltage drop at each node.
Calculations
(voltage drop across)
V1 = Vs – 10.00 = 15.00 – 10.00 = 5v
(voltage drop across) V2 = 10.00v – 5.00v = 5v
(voltage drop across) V3 = 5.00v – 0v = 5v
Conclusion
We found that in the same resistance of the
resistors, the voltage drops at each resistor is equal.
|
V1 + V2
+ V3 - VS = 0
|
KIRCHOOFF VOLTAGE LAW
5v + 5v + 5v – 15v = 0v
HENCE KIRCHOOFF`S VOLTAGE LAW PROVED…
But in case-II when the resistors are changed i.e. R1 ≠ R2 ≠ R3 , the voltage drop will not be the same
in each resistor.
Figure 2
Calculation
(voltage drop across)
V1 = Vs – 15.00 = 30.00 – 15.00 = 15v
(voltage drop across) V2 = 15.00v – 3.000v =12v
(voltage drop across) V3 = 3.000v – 0v = 3v
Conclusion
The voltage drop across different resistance
of resistors are different.
|
V1 + V2
+ V3 - VS = 0
|
KIRCHOOFF VOLTAGE LAW
3v + 12v + 15v – 30v = 0v
HENCE KIRCHOOFF`S VOLTAGE LAW PROVED…
If we have given the value of the SOURCE VOLTAGE (Vs)
and Total
Resistance ( Req ), we can easily find out the value of the each
voltage and prove the KIRCHOOFF`S VOLTAGE
LAW.
Calculation
Given data
Vs = 30v
Req = 10k Ω
To find
I =?
V1 =?
V2 =?
V3 =?
Solution
As: Vs
= I Req
|
|
I =
V1 = IR1 = 3mA*1k Ω = 3v
V2 = IR2 = 3mA*4k Ω = 12v
V3 = IR3 = 3mA*5k Ω = 15v
KIRCHOOFF VOLTAGE LAW
V1 + V2 + V3 - VS = 0 |
3v + 12v + 15v – 30v = 0v
HENCE KIRCHOOFF`S VOLTAGE LAW PROVED…
No comments:
Post a Comment